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6y^2=11y-5
We move all terms to the left:
6y^2-(11y-5)=0
We get rid of parentheses
6y^2-11y+5=0
a = 6; b = -11; c = +5;
Δ = b2-4ac
Δ = -112-4·6·5
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*6}=\frac{10}{12} =5/6 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*6}=\frac{12}{12} =1 $
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